2y^2-245y+4736=0

Solution for 2y^2-245y+4736=0 equation:

2y^2-245y+4736=0

a = 2; b = -245; c = +4736;
Δ = b2-4ac
Δ = -2452-4·2·4736
Δ = 22137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-245)-\sqrt{22137}}{2*2}=\frac{245-\sqrt{22137}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-245)+\sqrt{22137}}{2*2}=\frac{245+\sqrt{22137}}{4}
$